设为首页 加入收藏

TOP

HDU5014:Number Sequence
2015-07-20 17:40:49 来源: 作者: 【 】 浏览:2
Tags:HDU5014:Number Sequence
Problem Description There is a special number sequence which has n+1 integers. For each number in sequence, we have two rules:

● a i ∈ [0,n]
● a i ≠ a j( i ≠ j )

For sequence a and sequence b, the integrating degree t is defined as follows(“?” denotes exclusive or):

t = (a 0 ? b 0) + (a 1 ? b 1) +???+ (a n ? b n)


(sequence B should also satisfy the rules described above)

Now give you a number n and the sequence a. You should calculate the maximum integrating degree t and print the sequence b.

Input There are multiple test cases. Please process till EOF.

For each case, the first line contains an integer n(1 ≤ n ≤ 10 5), The second line contains a 0,a 1,a 2,...,a n.

Output For each case, output two lines.The first line contains the maximum integrating degree t. The second line contains n+1 integers b 0,b 1,b 2,...,b n. There is exactly one space between b i and b i+1 (0 ≤ i ≤ n - 1). Don’t ouput any spaces after b n.

Sample Input
4
2 0 1 4 3

Sample Output
20
1 0 2 3 4

尽量错开对应位置的0,1即可,就是说将对应位的二进制按位取反了,当然不能用~符号
#include 
   
    
#include 
    
      #include 
     
       #include 
      
        #include 
       
         #include 
         #include 
         
           using namespace std; #define ll __int64 #define up(i,x,y) for(i=x;i<=y;i++) #define up2(i,x,y) for(i=x;y;i++) #define down(i,x,y) for(i=x;i>=y;i--) #define down2(i,x,y) for(i=x;y;i--) #define mem(a,b) memset(a,b,sizeof(a)) #define s(a) scanf("%d",&a) #define s64(a) scanf("%I64d",&a) #define w(a) while(a) int n,a[100005],i,hash[100005]; int main() { w(~s(n)) { up(i,0,n) s(a[i]); printf("%I64d\n",(ll)n*n+n); mem(hash,-1); down(i,n,0) { if(hash[i]>=0) continue; int num=0,s=1,t=i; w(t) { int tem=((t&1)^1); num=num+s*tem; s*=2; t=t/2; } hash[num]=i; hash[i]=num; } printf("%d",hash[a[0]]); up(i,1,n) printf(" %d",hash[a[i]]); printf("\n"); } return 0; } 
         
       
      
     
    
   


】【打印繁体】【投稿】【收藏】 【推荐】【举报】【评论】 【关闭】 【返回顶部
分享到: 
上一篇POJ 2484 A Funny Game(博弈) 下一篇hdu 5017 Ellipsoid(三分)

评论

帐  号: 密码: (新用户注册)
验 证 码:
表  情:
内  容:

·用 C 语言或者限制使 (2025-12-25 08:50:05)
·C++构造shared_ptr为 (2025-12-25 08:50:01)
·既然引用计数在做 GC (2025-12-25 08:49:59)
·Java 编程和 c 语言 (2025-12-25 08:19:48)
·. net内存管理宝典这 (2025-12-25 08:19:46)