//nim博弈
//有n堆石头，两人轮流每次从一堆中拿至少1，之多全部的石头，没有石头可拿为lose
//判断先手是win还是lose
# include 
  
   
# include 
   
     # include 
    
      using namespace std; int main() { int n,i; __int64 a,sum; while(~scanf("%d",&n)) { sum=0; for(i=0; i