std::find_first_of

• C++98
• C++11

• equality (1)	template ForwardIterator1 find_first_of (InputIterator first1, InputIterator last1, ForwardIterator first2, ForwardIterator last2);
  predicate (2)	template ForwardIterator1 find_first_of (InputIterator first1, InputIterator last1, ForwardIterator first2, ForwardIterator last2, BinaryPredicate pred);

  Find element from set in range Returns an iterator to the first element in the range [first1,last1) that matches any of the elements in [first2,last2). If no such element is found, the function returns last1.
  

  返回一个迭代器，指向范围[first1,last1)中第一个匹配到[first2,last1)中的任一(并不要求全部匹配)元素。如果没有匹配的，则返回last1.

  例子：

  ?

  #include 
       
        
  #include 
        
          #include 
         
           #include 
          
            using namespace std; void findfirstof() { vector
           
             v1{1,2,3,4,5,6,3,4,9,8}; int arr[]={4,8}; array
            
              ai{77,88}; cout<
             
              例子：
              
  ?
              
   可以看到，只要匹配到一个元素符号要求，就返回。
   The elements in 
              [first1,last1) are sequentially compared to each of the values in 
              [first2,last2) using 
              operator== (or
              pred, in version 
              (2)), until a pair matches.
              
  [first1,last1)中的每一个元素依次和[first2,last2)中的每一个元素匹配，直到一个匹配出现。
              
  The behavior of this function template is equivalent to:
              
  （仔细看下面的代码就能看出来）
              
  
               
  
               
  
                
  
                 
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