Description

Poetry is a form of literature that uses aesthetic and rhythmic qualities of language. There are many famous poets in the contemporary era. It is said that a few ACM-ICPC contestants can even write poetic code. Some poems has a strict rhyme scheme like "ABABA" or "ABABCAB". For example, "niconiconi" is composed of a rhyme scheme "ABABA" with A = "ni" and B = "co".

More technically, we call a poem pretty if it can be decomposed into one of the following rhyme scheme: "ABABA" or "ABABCAB". The symbol A, B and C are different continuous non-empty substrings of the poem. By the way, punctuation characters should be ignored when considering the rhyme scheme.

You are given a line of poem, please determine whether it is pretty or not.

Input

There are multiple test cases. The first line of input contains an integer T indicating the number of test cases. For each test case:

There is a line of poem S (1 <= length(S) <= 50). S will only contains alphabet characters or punctuation characters.

Output

For each test case, output "Yes" if the poem is pretty, or "No" if not.

Sample Input

3
niconiconi~
pettan,pettan,tsurupettan
wafuwafu

Sample Output

Yes
Yes
No

题意：求满足"ABABA" or "ABABCAB"组合的字符串
思路：暴力求A和B，推出C
#include 
   
    
#include 
    
      #include 
     
       #include 
      
        using namespace std; int main() { int t; char ch[60]; scanf("%d", &t); while (t--) { string str; scanf("%s", ch); int len = strlen(ch); for (int i = 0; i < len; i++) if (isalpha(ch[i])) str += ch[i]; len = str.length(); int flag = 0; for (int i = 1; i < len/2 && !flag; i++) for (int j = 1; j < len/2 && !flag; j++) { string A = str.substr(0, i); string B = str.substr(i, j); if (A == B) continue; if (A + B + A + B + A == str) { flag = 1; continue; } if (len - (i + j) * 3 > 0) { string AB = A + B; string C = str.substr(2*(i+j), len-3*(i+j)); if (A == C || B == C) continue; if (AB + AB + C + AB == str) { flag = 1; continue; } } } if (flag) printf("Yes\n"); else printf("No\n"); } return 0; }