问题:
Sql 为：
select s.stagename sname,
sum(nworkhours) nworkhours,
sum(OVERHOURS) OVERHOURS,
sum(nworkhours+OVERHOURS)
from T_WorkDetails w,
t_stage s
where w.stageid=s.stageid and w.projectid='D0927380468F4A4EE04010AC0C051F15'
group by s.stagename
ORDER by s.stagename
显示为：
第二个SQL 为：
select sum(total) as temptal from (select s.stagename sname,
sum(nworkhours) nworkhours,
sum(OVERHOURS) OVERHOURS,
sum(nworkhours+OVERHOURS) total
from T_WorkDetails w,
t_stage s
where w.stageid=s.stageid and w.projectid='D0927380468F4A4EE04010AC0C051F15'
group by s.stagename
ORDER by s.stagename)
显示为：
想要显示的结果为：
核心思想：select * from (表A,表B)
总体的sql如下：
select * from (select s.stagename sname,
sum(nworkhours) nworkhours,
sum(OVERHOURS) OVERHOURS,
sum(nworkhours+OVERHOURS)
from T_WorkDetails w,
t_stage s
where w.stageid=s.stageid and w.projectid='D0927380468F4A4EE04010AC0C051F15'
group by s.stagename
ORDER by s.stagename) t1,
(select sum(total) as temptal from (select s.stagename sname,
sum(nworkhours) nworkhours,
sum(OVERHOURS) OVERHOURS,
sum(nworkhours+OVERHOURS) total
from T_WorkDetails w,
t_stage s
where w.stageid=s.stageid and w.projectid='D0927380468F4A4EE04010AC0C051F15'
group by s.stagename
ORDER by s.stagename)t2)
注意：行数少的那一张表会自动补齐行数和行数多的那一张表对应