Oracle函数 通过秒数或分钟数获取时间段

一同事叫帮忙写个函数，通过输入分钟数或秒数，获取一个时间段，尽管很简单，也还是贴出来一备需要的时候，直接拿来用：

create or replace function get_time(i_time in number, flag in varchar2) return varchar2 is

Result varchar2(100);

/*

i_time : 输入的时间数字

flag ：分钟还是秒的判断 0：分钟；1：秒

*/

total_ss number;

total_mi number;

total_Second number;

total_hh number;

total_minus number;

begin

if flag = '0' then

total_ss := i_time*60;

else

total_ss := i_time;

end if;

total_mi := trunc(total_ss/60);

total_Second := mod(total_ss,60);

if total_mi >=60 then

total_hh := trunc(total_mi/60);

total_minus := mod(total_mi,60);

else

total_hh := 0;

total_minus := total_mi;

end if;

if total_mi = 0 then

Result := to_char(total_Second)||'秒';

elsif total_hh = 0 then

Result := to_char(total_minus)||'分'||to_char(total_Second)||'秒';

elsif total_hh >0 then

Result := to_char(total_hh)||'时'||to_char(total_minus)||'分'||to_char(total_Second)||'秒';

else

Result := 'error';

end if;

return(Result);

end get_time;