Oraclesubstr函数用法

2015-01-25 19:30:43 · 作者: · 浏览: 3

oracle的substr函数的用法
\ 取得字符串中指定起始位置和长度的字符串 substr( string, start_position, [ length ] )
\ 如:
\ substr('This is a test', 6, 2) would return 'is'
\ substr('This is a test', 6) would return 'is a test'
\ substr('TechOnTheNet', -3, 3) would return 'Net'
\ substr('TechOnTheNet', -6, 3) would return 'The'

select substr('Thisisatest', -4, 2) value from dual 结果是 te

select substr('emros',-3,1) value from dual 结果是 r

substr('abcde',-6) = null
substr('abcde',-5) = 'abcde'
substr('abcde',-4) = 'bcde'
substr('abcde',-3) = 'cde'
substr('abcde',-2) = 'de'
substr('abcde',-1) = 'e'
substr('abcde',-0) = 'abcde'