java将xml解析,然后将其转换为json格式(②)

2014-11-24 02:31:43 · 作者: · 浏览: 0

但是如果是两个model呢!因为我写的项目中就是需要用两个model获取!我先把我项目中从后台接收的xml列出来!


  
 
  
   
   
    true
   
   
    
     
     
      0
      
     
      Normal
      
     
      正常
      
     
     
     
      0
      
     
      Normal
      
     
      暂停
      
    
 
  

要想解析这样的model需要用另外一种格式:

import java.util.ArrayList;
import java.util.List;
import net.sf.json.JSONArray;
import net.sf.json.JSONObject;

/**
 * 将model存在list集合中,并将集合转换为json格式
 * */
public class xmlJdom {
	public static void main(String[] args) {
		Student s1=new Student();
		s1.setAge(123);
		s1.setNameString(name);
		Student s2=new Student();
		s2.setAge(1234);
		s2.setNameString(what);
		Teacher teacher=new Teacher();
		teacher.setsAge(11);
		teacher.setsName(teacher);
		List
  
    lists=new ArrayList
   
    (); lists.add(s1); lists.add(s2); teacher.setStudent(lists); new JSONObject(); JSONObject jsonObject = JSONObject.fromObject(teacher); System.out.println(jsonObject); List
    
      list = new ArrayList
     
      (); list.add(s1); list.add(s2); JSONArray jsonArr= JSONArray.fromObject(list); System.out.println(jsonArr); } } 
     
    
   
  

输出的内容为:

{sAge:11,sName:teacher,student:[{age:123,nameString:name},{age:1234,nameString:what}]}
[{age:123,nameString:name},{age:1234,nameString:what}]


两个model:Student和Teacher

teacher里面包含student的list集合:

public class Student {  
  
    private String nameString;  
    private int age;  
    
    public String getNameString() {  
        return nameString;  
    }  
    public void setNameString(String nameString) {  
        this.nameString = nameString;  
    }  
    public int getAge() {  
        return age;  
    }  
    public void setAge(int age) {  
        this.age = age;  
    }  
      
}  

import java.util.List;


public class Teacher {
	private String sName;
	private int sAge;
	private List
  
    student;
	public List
   
     getStudent() { return student; } public void setStudent(List
    
      student) { this.student = student; } public String getsName() { return sName; } public void setsName(String sName) { this.sName = sName; } public int getsAge() { return sAge; } public void setsAge(int sAge) { this.sAge = sAge; } } 
    
   
  

这样就ok!现在已经学会了举一反三了!

如需转载请注明出处:Finder_畅畅