题目：
Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
You may assume no duplicates in the array.
Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6], 0 → 0
分析：此题和上一题类似，就是利用二分搜索查找数字。
具体代码如下：
int searchInsert(int A[], int n, int target) {
if(n<=0)return 0;
int l=0,r=n-1,m=l+(r-l)/2;
while(l
if(A[m]>=target)r=m;
if(A[m]
}
if(A[m]>=target)
return m;
return m+1;
}