/*
* 解题思路：
* 题意容易理解，可以画图分析，发现只要对立面都匹配就为True！
*/
#include#include int vis[ 15 ]; char s1[ 8 ],s2[ 8 ]; int compare( int x , int y ,int a,int b,int c,int d ) { if( !vis[ x ] && !vis[ y ] && ((s2[ x ] == s1[ x ] && s2[ y ] == s1[ y ] ) || (s2[ y ] == s1[ x ] && s2[ x ] == s1[ y ] )) ) { vis[ x ] = vis[ y ] = 1; return 1; } else if( !vis[ a ] && !vis[ b ] && (( s2[ a ] == s1[ x ] && s2[ b ] == s1[ y ]) || ( s2[ b ] == s1[ x ] && s2[ a ] == s1[ y ])) ) { vis[ a ] = vis[ b ] = 1; return 1; } else if( !vis[ c ] && !vis[ d ] && ((s2[ c ] == s1[ x ] && s2[ d ] == s1[ y ] ) || (s2[ d ] == s1[ x ] && s2[ c ] == s1[ y ] )) ) { vis[ c ] = vis[ d ] = 1; return 1; } return 0; } int main( ) { int i; int sum; while( ~scanf("%c%c%c%c%c%c%c%c%c%c%c%c",&s1[0],&s1[1],&s1[2],&s1[3],&s1[4],&s1[5],&s2[0],&s2[1],&s2[2],&s2[3],&s2[4],&s2[5]) ) { getchar( ); sum = 0; memset(vis,0,sizeof(vis)); sum += compare( 0 , 5 , 1 , 4 , 2 , 3 ); sum += compare( 1 , 4 , 0 , 5 , 2 , 3 ); sum += compare( 2 , 3 , 1 , 4 , 0 , 5 ); if( sum == 3 ) printf("TRUE\n"); else printf("FALSE\n"); } return 0; }